关于如何读取XML文件的一个简单方法

<?xml version="1.0"?>
<YearLeaveConfig xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<!--下列标签首字母必须大写-->
  <LeaveItems>
    <LeaveItem>
      <YearStart>0</YearStart>
      <YearEnd>1</YearEnd>
      <LeaveDay>0</LeaveDay>
    </LeaveItem>

    <LeaveItem>
      <YearStart>1</YearStart>
      <YearEnd>2</YearEnd>
      <LeaveDay>2</LeaveDay>
    </LeaveItem>

    <LeaveItem>
      <YearStart>2</YearStart>
      <YearEnd>5</YearEnd>
      <LeaveDay>3</LeaveDay>
    </LeaveItem>

    <LeaveItem>
      <YearStart>5</YearStart>
      <YearEnd>8</YearEnd>
      <LeaveDay>6</LeaveDay>
    </LeaveItem>

    <LeaveItem>
      <YearStart>8</YearStart>
      <YearEnd>100</YearEnd>
      <LeaveDay>10</LeaveDay>
    </LeaveItem>
    
  </LeaveItems>
</YearLeaveConfig>

public class LeaveItem
    {
        public int YearStart { get; set; }
        public int YearEnd { get; set; }
        public int LeaveDay { get; set; }
    }

    public class YearLeaveConfig
    {
        public LeaveItem[] LeaveItems { get; set; }
    }

static void Main(string[] args)
        {
            string strPth = Environment.CurrentDirectory;
            YearLeaveConfig yearLeave = (YearLeaveConfig)new XmlSerializer(typeof(YearLeaveConfig)).Deserialize(new FileStream(strPth + @"\YearLeaveConfig.xml", FileMode.Open));

            foreach (LeaveItem item in yearLeave.LeaveItems)
            {
                Console.WriteLine(string.Format("年假设置：{0}~~{1}年的享受年假：{2}天",item.YearStart,item.YearEnd,item.LeaveDay));
                
            }
            Console.Read();

        }