测试环境：
SQL2005个人开发者版 SP4
SQLPROMPT版本：5.3.8.2
视图
1 CREATE VIEW aa 2 WITH ENCRYPTION 3 AS 4 SELECT * FROM [dbo].[Users]
可以解密
存储过程
1 CREATE PROCEDURE bb 2 WITH ENCRYPTION 3 AS 4 SELECT * FROM [dbo].[Users]
可以解密
触发器
1 CREATE TRIGGER cc 2 ON [dbo].[Users] 3 WITH ENCRYPTION 4 FOR INSERT 5 AS RAISERROR(500001,16,10)
触发器不能手动调用的，所以不能解密
函数
1 USE [pratice] 2 GO 3 CREATE FUNCTION [dbo].f_get_page(@page_num BINARY(6)) 4 RETURNS VARCHAR(11) 5 WITH ENCRYPTION 6 AS 7 BEGIN 8 RETURN(CONVERT(VARCHAR(2),(CONVERT(INT,SUBSTRING(@page_num,6,1))*POWER(2,8))+ 9 (CONVERT(INT,SUBSTRING(@page_num,5,1))))+‘:‘+ 10 CONVERT(VARCHAR(11), 11 (CONVERT(INT,SUBSTRING(@page_num,4,1))*POWER(2,24))+ 12 (CONVERT(INT,SUBSTRING(@page_num,3,1))*POWER(2,16))+ 13 (CONVERT(INT,SUBSTRING(@page_num,2,1))*POWER(2,8))+ 14 (CONVERT(INT,SUBSTRING(@page_num,1,1))))) 15 END
可以解密
如有不对的地方，欢迎大家拍砖o(∩_∩)o
SQLPROMPT5.3对各种加密对象的解密测试,布布扣,bubuko.com
原文：http://www.cnblogs.com/lonelyxmas/p/3584235.html